Extension of spring - Hooke's Law?
I have this question:
A spring is originally 12cm long. When a load of 0.2N is hanged, the spring becomes 12.5cm long. Now, a load of 5N is hanged and the extension of the spring is 20cm.
Why the extension is so large?
Extension of spring - Hooke's Law?opera mobileRubber is generally regarded as a "non-hookean" material because its elasticity is stress dependent and sensitive to temperature and loading rate.
Hook's law is not obeyed by rubber.
Extension of spring - Hooke's Law?imax theatre opera theater
cause the relationship between gravity and mass. i dont know the exact equation though|||because for every .2N u add the spring will extend .5cm. so if you have 1N that will add about 2.5cm to the spring. now if u place 5N on a 12cm spring it should extend to, if i added right, around 22.5cm in length. 5N=10.5cm extension in your 12cm spring. i don't know how u got 20 but hey, 22.5 is pretty close to 20|||The equation for extension,dL=(F*L) /(A * Y)
F--force
L-original length
A-area of cross section
Y-yong's modulus
In this particular case, Y& L doesnot change.
As F increases,extension increases...
In additon to that, when F increases,a lateral strain is developed, which reduces the area of cross section of the spring.Thus there is a considerable increase in extension.
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