Circular motion help?

I am lost in this problem. Can someone show me the steps in how to do it so I can learn the process of it and how to solve it?

Computer-controlled display screens provide drivers in the Indianapolis 500 with a variety of information about how their cars are performing. For instance, as a car is going through a turn, a speed of 236 mi/h (105.492 m/s) and a centripetal acceleration of 2.00g (two times the acceleration due to gravity) are displayed. Determine the radius of the turn (in meters).

Circular motion help?headache

Ok, first you must get the centripetal acceleration equation, which is:

Ac = V2/R or W2*R

where v2 is the tangencial velocity squared, R is the radius and W is the angular velocity. In this case we'll use the first expression

R = V2/Ac since we know both things, we just substitute:

R = (105.492 m/s)squared/(2*9.81m/s2) = 567.2 m

Hope this helps.

Circular motion help?paramount theater opera theater

Consider :

centripital accel., a = v^2 x r

angular velocity = linear velocity/r

Thus, 2 x (9.8) = (105.492/r)^2 x r

radius, r = (105.492)^2/19.6

radius,r = 567.78 meters

Circular motion help?

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